Question

In: Physics

Question #1 What is the ratio of the suns gravitational force on you to the earths...

Question #1

What is the ratio of the suns gravitational force on you to the earths gravitational force on you?

Please slove this by step by step and explain the steps. Thank you.

Question #2

A)What is the gravitational force of the sun on the earth?

B) What is the gravitational force of the moon on the earth?

C) The moon's force is what percent of the suns force?

Please slove this by step by step and explain the steps. Thank you.

Solutions

Expert Solution

A.   Fg= G*(m/r^2).

The Mass of the Earth = 5.98*10^24 kg.
The Mass of the Sun = 1.99*10^30 kg.
The Radius Of The Earth =6,378,100m
The Radius Of the Orbit Of The Earth = 1.5*10^11m.
The Radius Between You And The Sun = The radius of the sun subtracted from the radius of the eath's orbit around the Sun = (1.5*10^11m. - 6,378,100m) = 1.499936219*10^11m

So the Ratio is the Fg of The Sun Divided By The Fg of the Earth.
Dividing the two makes:

(G*(Ms/Re^2))/(G*(Me/Rs^2)
Where G is the gravitational Constant = 6.67*10^-11.
Rs=Radius between YOU and the Sun (Not the radius of the sun)

The G terms cancel and leave you with the (Ms/Rs^2)/(Me/Re^2)

Mulitplying the denominator by its Reciprical Leaves ((Ms)(Re^2))/(Me*Rs^2))

((1.99*10^30)((6,378,100m)^2)/((5.98*10^24*(1.49*10^11)^2

= (8.095351762*10^43)/(1.345385579*10^47)

= 6.0 * 10^-4 = Ratio of F(sun)/F(earth)

B1. The r refers to the distance between the centre of the earth and the centre of the sun, which is 1.5*10^ 11m
F = (6.67*10^-11 * 6.0*10^24 * 2.0*10^30)/ (1.5*10^11)


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