A 9.0 V potential difference is applied between the ends of a 0.60-mm diameter, 80-cm long...

A 9.0 V potential difference is applied between the ends of a 0.60-mm diameter, 80-cm long nichrome wire. What is the current in the wire?

Expert Solution

Potential difference across the ends of wire,V=9 V

Diameter of wire ,d=0.60 mm=0.6010-3 m

Area of wire,A=(d/2)2=(0.6010-3/2)2=2.8310-7 m2

Length of wire,L=80 cm=0.80 m

Resistivity of nichrome wire,=1.110-6 ohm-m

So

Resistance of wire,R=L/A=(1.110-60.80)/(2.8310-7)=3.1 ohm

So

Current in the wire=V/R=9/2.83=3.18 A

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genius_generous answered 2 years ago

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