Question

In: Physics

In the figure below, the battery has potential difference V = 9.0 V, C2 = 3.0

Expert Solution

charge passes through the b point is nothing but the charge present on the c4 capacitor.

charge on c4=7.2uC

voltage across c4=chare/capacitance=7.2u/4.5u=7.2/4.5=1.6 volts=Vc4

cahge passes through the point a.

this charge is divided and some amount of charge passes through the point b and some amount of charge passes through the c3 capacitor.

amont of cahrge passes through the C3=charge passes through the point a -charge passes through the point b

charge on c3=12 u-7.5u=4.8uC

C3 and c4 are in conneced in parallel.

so voltage across c4=voltage across c3=1.6v=Vc3

capacince value of c4=charge/voltage=4.8u/1.6=3 uF

charge passes through point a is also passes through the c1 and c2.

so charge passes through capacitors is same i.e 12uC

so voltage across v2=charge/capacitance=12u/3u=4 volts=Vc2

apply kvl in loop that containing v+, c1,c2,c3,v-

v-Vc1-Vc2-Vc3=0

9-Vc1-3-1.6=

Vc1=4.4 volts

charge passes through point a is also passes through the c1 and c2.

so charge passes through capacitors is same i.e 12uC

capacitance value =C1=charge/voltage=12u/4.4=2.7272 uC

genius_generous answered 8 months ago

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