The metabolic oxidation of glucose, C6H12O6, in our body produces CO2, which is expelled from our...

The metabolic oxidation of glucose, C6H12O6, in our body produces CO2, which is expelled from our lungs as a gas: C6H12O6(aq) + O2(g) → CO2(g) + H2O(g) If 11.8 L of dry CO2 was produced at a slightly elevated body temperature (39°C) and 902 mm Hg, what mass of glucose was oxidized?

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Expert Solution

Moles of CO2 produced = n= pv/RT

P= 902/760= 1.18 atm

n= 1.18* 11.8/0.0821*312

n= 0.543 moles.

I mole of glucose produces 6 moles of CO2so moles of glucose used= 0.543/6= 0.0905 moles

Mass = 180*0.0905= 16.29 gm

queen_honey_blossom answered 1 year ago

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