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When glucose, C6H12O6, is oxidized in our bodies energy is produced. In addition,CO2, is produced as...

When glucose, C6H12O6, is oxidized in our bodies energy is produced. In addition,CO2, is produced as a gas. The carbon dioxide gas eventualy finds its way from the cells to the lungs where it is expelled from the body. C6H12O6(aq) + 6 O2(g) → 6 CO2(g) + 6 H2O(l) + ENERGY Calculate the volume of dry CO2 produced at body temperature (37°C) and 0.980 atm when 23.1 g of glucose is consumed in this reaction. ________L Give the answer again with the correct number of significnt figures. _________ L

Solutions

Expert Solution

C6H12O6(aq) + 6 O2(g) → 6 CO2(g) + 6 H2O(l) + ENERGY

no of mol of glucose reacted = w/mwt = 23.1/180 = 0.1283 mole

no of mole of CO2 produced = 6*0.1283 = 0.7698 mol

volume of CO2 produced = nRT/P

                                  = 0.7698*0.0821*310 / 0.98

                                   = 19.99 L

volume of CO2 with correct number of significnt figures = 20 L

queen_honey_blossom answered 2 years ago
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