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The metabolic oxidation of glucose, C6H12O6 , in our bodies produces CO2, which is expelled from...

The metabolic oxidation of glucose, C6H12O6 , in our bodies produces CO2, which is expelled from our lungs as a gas:
C6H12O6(aq)+6O2 (g)→6CO2 (g)+6NH3 (l)
Calculate volume of dry CO2 produced at 37 °C and 0.970 atm when 24.5 g of glucose is
consumed.
A) 0.43 L B) 3.57 L C) 6.84 L D) 14.61 L E) 21.43 L

Solutions

Expert Solution

Moles of glucose = mass / molar mass = 24.5 / 180 = 0.1361 mol

From the equation, moles of CO2 = 6 * moles of glucose = 6 * 0.1361 = 0.817 mol

Using the ideal gas equation: Volume (V) = nRT / P, where n is numbe rof moles, R is gas constant, T is temperature in K (273 + 37 = 310 K) and P is pressure

V = 0.817 * 0.0821 * 310 / 0.97 = 21.43 Liters

queen_honey_blossom answered 2 years ago
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