In: Chemistry
in a certain operation 3.54*104 kg of Ticl4 is reacted with 1.13*104 kg of Mg
A) Calculate the theoretial yield of titanium , Ti in
kilograms.
B ) Calculate the percent yield if 7.91*103 kg of Ti is
actually obtained
(Ti : 47.88 , Mg: 24,3, Cl; 35.5)
Help please with explain every thing :)
A. Mass of TiCl4=3.54*104 kg
Moles of TiCl4=3.54*104/189.88=186.433 kmol
Moles of Mg=1.13*104/24.3=465.02 kmol
Reaction occurring is:
TiCl4 +2Mg =2MgCl2 +Ti
As moles of Mg> 2*moles of TiCl4 hence TiCl4 is limiting reagent.
Moles of Ti produced=Moles of TiCl4=186.433 kmol
Theoretical yield of Ti= 47.88*186.433=8926.3 kg=8.9263*103 kg
B. Percent yield=(Actual yield/Theoretical yield)*100
=(7.91*103/8.9263*103)100=88.7%