2H2S(g)<---> 2H2(g) + S2(g) The value of Kc for the thermal decomposition of hydrogen sulfide is...

2H2S(g)<---> 2H2(g) + S2(g)

The value of Kc for the thermal decomposition of hydrogen sulfide is 2.2x10^-4 at 1400 K. A sample of gas which [H2S]=4.60 M is heated to 1400 K in a sealed vessel. After chemical equilibrium has been achieved, what is the value of [H2S] in M? Assume no H2 or S2 was present in the original sample.

Solutions

Expert Solution

2H2S(g)<---> 2H2(g) + S2(g)

I 4.6 0 0

C -2x 2x x

E 4.6-2x 2x x

Kc = [H2]^2[S2]/[H2S]^2

2.2*10^-4 = (2x)^2*x/(4.6-2x)^2

2.2*10^-4 *(4.6-2x)^2 = 4x^3

x = 0.102

[H2S] = 4.6-2x = 4.6-2*0.102 = 4.396M

[H2} = 2x = 2*0.102 = 0.204M

[S2] = x = 0.102M

queen_honey_blossom answered 1 month ago

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