In: Chemistry
2 h2s(l) ⇌ 2h2(g) + s2(g) (Kc at 700c is 9.30x10^-8)
A) Write the equilibrium expression for this reaction
B) If 0.45 mol of H2S gas is placed in a 3 L container at 700C what is the concentration, in mol/L, of hydrogen gas when equilibrium is reached.
A ) equilibrium expression Kc = [H2]^2 [S2]
pure liquid doesnot take in the part of equilibrium expression
B)
molarity of H2S = 0.45 / 3 = 0.15 M
2H2S (l) <---------------------> 2H2 (g) + S2 (g)
0.15 0 0 ---------------> iniitla
0.15-2x 2x x ------------------> equilibrium
Kc = [H2]^2 [S2]
Kc = (2x)^2 (x)
Kc = 4 x^3
9.30 x 10^-8 = 4 x^3
x = 2.85 x 10^-3
equilibrium concentrations :
hydrogen equilibrium concentration = 2x = 5.71 x 10^-3 M
sulfur equilibrium concentration = x = 2.85 x 10^-3 M