Three point charges are placed on the y-axis, a charge q at y=a, a charge -2q...

Three point charges are placed on the y-axis, a charge q at y=a, a charge -2q at the origin and a charge q at y=-a. Such an arrangement is called an electric quadrupole. (a) Find the magnitude and direction of the electric field at points on the positive x-axis. (b)What would be the force exerted by these three charges on a fourth charge 2q placed at (b,0). Explain the steps along the way and thought process behind solving.

Solutions

Expert Solution

Electric field=K Q/(distance)^2

Taking vector comments in consideration Electric field taken into Its X and Y components.

And X components can be given by Ex=KQx/R^3

Where R=√(x^²+y^²)

Force at a point given by electric field at that point × Charge residing at that point

i.e F=QE

genius_generous answered 1 year ago

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