In: Math
General guidelines:
Use EXCEL or PHStat to do the necessary computer work.
Do all the necessary analysis and hypothesis test constructions, and explain completely.
Read the textbook Chapter 11. Solve the textbook example on page 403, "Mobile Electronics," in order to compare four different in-store locations with respect to their average sales.
Use One-Way ANOVA to analyze the data set, data, given for this homework.
Use 5% level of significance.
1) Do the Levene test in order to compare the variance of the sales level at four different in-store locations.
2) If there are no significant differences between the variance of sales, then conduct the one-way ANOVA hypothesis test to compare the average sales level at four different in-store locations.
3) If you have seen evidence of difference among the average sales levels at these four different in-store locations, then identify which in-store locations have significantly different average sales than other in-store locations, by using the Tukey procedure
Data Set:
|
MINITAB used for analysis.
Use One-Way ANOVA to analyze the data set, data, given for this homework. Use 5% level of significance.
1) Do the Levene test in order to compare the variance of the sales level at four different in-store locations.
Test for Equal Variances: Inasile, front, kiosk, expert
Method
Null hypothesis |
All variances are equal |
Alternative hypothesis |
At least one variance is different |
Significance level |
α = 0.05 |
95% Bonferroni Confidence Intervals for Standard Deviations
Sample |
N |
StDev |
CI |
Inasile |
5 |
1.03403 |
(0.180537, 11.8340) |
front |
7 |
0.46824 |
(0.161813, 2.1066) |
kiosk |
8 |
0.35848 |
(0.094007, 1.9875) |
expert |
6 |
0.17646 |
(0.053434, 0.9983) |
Individual confidence level = 98.75%
Tests
Method |
Test |
P-Value |
Multiple comparisons |
— |
0.133 |
Levene |
0.68 |
0.575 |
Calculated Levene test value = 0.68, P=0.575 which is > 0.05 level of significance. Ho is not rejected. We conclude that variance of the sales level at four different in-store locations are equal.
2) If there are no significant differences between the variance of sales, then conduct the one-way ANOVA hypothesis test to compare the average sales level at four different in-store locations.
One-way ANOVA: Inasile, front, kiosk, expert
Method
Null hypothesis |
All means are equal |
Alternative hypothesis |
Not all means are equal |
Significance level |
α = 0.05 |
Equal variances were assumed for the analysis.
Factor Information
Factor |
Levels |
Values |
Factor |
4 |
Inasile, front, kiosk, expert |
Analysis of Variance
Source |
DF |
Adj SS |
Adj MS |
F-Value |
P-Value |
Factor |
3 |
21.606 |
7.2020 |
23.83 |
0.000 |
Error |
22 |
6.648 |
0.3022 |
||
Total |
25 |
28.254 |
Model Summary
S |
R-sq |
R-sq(adj) |
R-sq(pred) |
0.549694 |
76.47% |
73.26% |
65.06% |
Means
Factor |
N |
Mean |
StDev |
95% CI |
Inasile |
5 |
29.582 |
1.034 |
(29.072, 30.092) |
front |
7 |
32.139 |
0.468 |
(31.708, 32.569) |
kiosk |
8 |
30.758 |
0.358 |
(30.354, 31.161) |
expert |
6 |
30.2783 |
0.1765 |
(29.8129, 30.7437) |
Pooled StDev = 0.549694
Calculated F test value = 23.83, P=0.000 which is< 0.05 level of significance. Ho is rejected. We conclude that average sales level at four different in-store locations are not same .
3) If you have seen evidence of difference among the average sales levels at these four different in-store locations, then identify which in-store locations have significantly different average sales than other in-store locations, by using the Tukey procedure.
Tukey Pairwise Comparisons
Grouping Information Using the Tukey Method and 95% Confidence
Factor |
N |
Mean |
Grouping |
||
front |
7 |
32.139 |
A |
||
kiosk |
8 |
30.758 |
B |
||
expert |
6 |
30.2783 |
B |
C |
|
Inasile |
5 |
29.582 |
C |
Means that do not share a letter are significantly different.
Tukey Simultaneous Tests for Differences of Means
Difference of Levels |
Difference |
SE of |
95% CI |
T-Value |
Adjusted |
front - Inasile |
2.557 |
0.322 |
(1.662, 3.451) |
7.94 |
0.000 |
kiosk - Inasile |
1.175 |
0.313 |
(0.305, 2.046) |
3.75 |
0.006 |
expert - Inasile |
0.696 |
0.333 |
(-0.229, 1.621) |
2.09 |
0.187 |
kiosk - front |
-1.381 |
0.284 |
(-2.172, -0.590) |
-4.85 |
0.000 |
expert - front |
-1.860 |
0.306 |
(-2.710, -1.010) |
-6.08 |
0.000 |
expert - kiosk |
-0.479 |
0.297 |
(-1.304, 0.346) |
-1.61 |
0.392 |
Individual confidence level = 98.91%
Tukey procedure shows front and Inasile are significant.
kiosk and Inasile are significant.
kiosk are front are significant.
expert and front are significant.