use bisection to find the real root x = sin(x) + 1 with the initial guesses...

use bisection to find the real root x = sin(x) + 1 with the initial guesses of x l = 0 and x u = 3.

perform the computation until the approximate error falls below 5%

Expert Solution

Colby Messinger answered 2 years ago

Using the bisection method, find the root of the following function: f(x)=cos(2x) - x Use the...

Using the bisection method, find the root of the following function: f(x)=cos(2x) - x Use the following initial values: xl=0 and xu=2 NOTE: Perform only 3 iterations.

USING BISECTION METHOD, FIND THE ROOT OF 0.5e^x - 5x + 2 = 0 ON THE...

USING BISECTION METHOD, FIND THE ROOT OF 0.5e^x - 5x + 2 = 0 ON THE INTERVAL [ 0 , 1 ] UP TO 3 DECIMAL PLACES. USE NEWTON'S METHOD TO APPROXIMATE THE ROOT OF f(x)=x^2-5 IN THE INTERVAL [ 2 , 3 ] UP TO 4 DECIMAL PLACES.

Find the root of the function f(x) = 8 - 4.5 ( x - sin x...

Find the root of the function f(x) = 8 - 4.5 ( x - sin x ) in the interval [2,3]. Exhibit a numerical solution using Newton method.

Use false position method to find the root of ?(?) = −sin(? − 5) + ?...

Use false position method to find the root of ?(?) = −sin(? − 5) + ? with initial guesses of 0.2 and 1. Show up to three iterations and calculate the relative percent error ?? for each iteration possible? Show full details for at least one iteration to get full points. Also, if three significant figure accuracy is required, show if the value after third iteration is acceptable or not.

1. Locate a root of sin(x)=x2 where x is in radians. Use a graphical technique and...

1. Locate a root of sin(x)=x2 where x is in radians. Use a graphical technique and bisection with the initial interval from 0.5 to 1. Perform the computation until ea is less than es=2%. Also perform an error check by substituting your final answer into the original equation. 2. Determine the positive real root of ln(x 2 )=0.7 using three iterations of the bisection method, with initial interval of [0.5:2]. 3. Determine the lowest positive root of f(x)=7sin(x)e -x -1...

Estimate a real root of the polynomial f(x) = 5x4-2x3-25x2-6x+45 between x=1 and x=2 (using bisection,...

Estimate a real root of the polynomial f(x) = 5x4-2x3-25x2-6x+45 between x=1 and x=2 (using bisection, Standard Newton-Raphson, Secant, and modified Newton-Raphson, and modified Secant methods). Show the detailed calculations for 5 iterations (for each method)

Use the bisection method to approximate the root of f(x)=x-cosx in the range [0.0,1.5]. Stop when...

Use the bisection method to approximate the root of f(x)=x-cosx in the range [0.0,1.5]. Stop when the error is less than 0.002%

f(x)=x^3-3x-1=0 x=[0,2] epsilon=5*10^-2 1. perform the bisection method for the root in [0,2] until your root...

f(x)=x^3-3x-1=0 x=[0,2] epsilon=5*10^-2 1. perform the bisection method for the root in [0,2] until your root is closer to the real root within epsilon. Let x_0=1.0, x_1=1.2 2. perform the secant method until your root is closer to the real root within epsilon. 3. do as in 2. with the Newton's method, with x_0=1.1

a) you can see a program for using bisection search to find the square root of...

a) you can see a program for using bisection search to find the square root of x: x = 25 epsilon = 0.01 low = 0.0 high = max(1.0, x) guess = (low + high) / 2 numberofguesses = 1 while abs(guess ** 2 - x) > epsilon : print('low =', low, 'high = ', high, 'guess = ', guess) if guess** 2 > x : # the guess is too high, so move high down to guess high =...

To find a positive root for , write a MATLAB script file that uses Bisection method....

To find a positive root for , write a MATLAB script file that uses Bisection method. Choose any initial value that is needed. Use absolute relative approximate error to be less than 0.01. Your code should report the number of iteration and the value of x.

Question