In: Mechanical Engineering
A radial flow hydraulic turbine whose design is based on a power specific speed, Ωsp=1.707 is to produce 25 MW from a total head, HE=25 m. The overall turbine efficiency ηo=0.92, the mechanical efficiency is 0.985, and the loss in head in the nozzles is 0.5 m. The ratio of the blade tip speed to jet speed is 0.90. Assuming the meridional velocity is constant and equal to 10 m/s and there is no swirl in the runner exit flow, determine
Given:
P = 25 × 106 W ηo = 0.92, ρ = 1000 kg/m3 g = 9.81 m/s2, HE = 25 m
Hence, the volume flow rate through the turbine is Q = 110.8 m3/s
Write expression for specific speed:
Calculate angular speed of turbine.
Given: Ωsp = 1.707, g = 9.81 m/s2 HE = 25 m, P = 25 × 106 W, ρ = 1000 kg/m3
Calculate rotational speed:
Therefore, rotational speed is N = 100.0567 rpm
Calculate blade tip speed.
Given: K = 0.9, g = 9.81 m/s2, HE = 25 m, h = 0.5 m
Calculate diameter of runner.
Given: U = 19.732 m/s, N = 100.0567 rpm
Therefore, the diameter is D = 3.766 m
Calculate hydraulic efficiency.
Given: ηo = 0.92, ηm = 0.985
Calculate swirl velocity at runner exit.
Given: ηh = 0.934, g = 9.81 m/s2, HE = 25 m, U = 19.732 m/s
Radial velocity at runner exit is the meridional velocity.
Calculate absolute flow angle at runner exit.
Given: cθ2 = 11.6087 m/s, cr2 = 10 m/s
Calculate relative flow angle at runner exit.
Given: cθ2 = 11.6087 m/s, U = 19.732 m/s, cr2 = 10 m/s
Hence, the absolute flow angle at runner exit is 49.26° and the relative flow angle at runner exit is -39.088°
There is the answer we calculate.