1) Suppose after charging a 5.8

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Expert Solution

1) You must use 4 principles in answering this: (a) since the caps are joined in parallel their final voltage (V) will be equal; (b) charge (Q) is conserved, so after having made the connection, the final charge wil be equal to the sum of the 2 initial charges; (c) Q = V*C in all cases (C = capacitance); (d) when caps are joined in parallel the total capacitance (Ctot) will be the sum of the individual capacitances.

C1 = 5.8*8 = 46.4uC C2 =4.4*8 = 35.2uC. Total charge = 81.6uC

V = 81.6/(5.8 + 4.4) = 8V

2) Let initial charge on 3.5uF cap be Q, that on 10uf cap be zero. Total charge = Q.

Q = V*C so for initial conditions Q = 5*3.5uC

For conditions when caps are in parallel V = Q/Ctot = 5*3.5/13.5 = 1.29V.

What happens after this is not clear. If the caps are separated and then re-joined the voltage will not change. If the caps are restored to their original states, and then re-joined the same result will be repeated.

genius_generous answered 3 weeks ago

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