A man stands on the roof of a building of height 13.4 m and throws a...

A man stands on the roof of a building of height 13.4 m and throws a rock with a velocity of magnitude 27.5 m/s at an angle of 32.8 ∘ above the horizontal. You can ignore air resistance.

1. Calculate the maximum height above the roof reached by the rock.

2. Calculate the magnitude of the velocity of the rock just before it strikes the ground.

3. Calculate the horizontal distance from the base of the building to the point where the rock strikes the ground.

Expert Solution

Diagram is shown AB is building of height 13.4 m.

Velocity of rock is = u

angle is shown in figure.

Two components of "u" are shown.

Maximum height above the roof is shown by H and is calculated.

For the next calculations first of all we will have to calculate the time taken by the rock to reach the ground. For this use second equation of motion in vertical direction.

Actually quadratic equation will form which i have solved directly using formula. It will give two values for time but negative value is not possible so t = 3.766 second is taken.

Solution is attached here on two scanned sheets.

genius_generous answered 6 months ago

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