In: Chemistry
What volume of 0.0100 M KMnO4 solution is required to oxidize 42.5 mL of 0.0190 M FeSO4 in sulfuric acid solution?
Number of moles of FeSO4 is , n = molarity x volume in L
= 0.0190 M x 0.0425 L
= 8.075 x 10 -4 moles
The reaction between KMnO4 & FeSO4 in acidic medium is
2 KMnO4 + 10 FeSO4 + 8 H2SO4 K2SO4 + 2MnSO4 + 5 Fe2(SO4)3 + 8 H2O
According to the balanced equation ,
10 moles of FeSO4 reacts with 2 moles of KMnO4
8.075 x 10 -4 moles of FeSO4 reacts with Z moles of KMnO4
Volume of KMnO4 is