In: Statistics and Probability
Suppose that X is a Normal random variable with mean 1.2 and standard deviation 0.5.
a. Find a value a such that P(X?a)=0.10.
b. Find a value b such that P(X?b)=0.10.
c. Find a value c such that P(1.2?c<X<1.2+c)=0.30.
Here we have
a:
Using excel function "=NORMSINV(0.1)", the z-score that has 0.10 area to its left is -1.28.
That is
We need to find a such that
The required a is
(b)
Using excel function "=NORMSINV(0.9)", the z-score that has 0.90 area to its left is 1.28.
That is
We need to find b such that
The required a is
(c)
Here we need z-score that has 0.35 area to its left. Using excel function "=NORMSINV(0.35)", the z-score that has 0.35 area to its left is -0.385.
So,
So,