The addition of a common ion has been shown to disturb a system at equilibrium. Naturally,...

The addition of a common ion has been shown to disturb a system at equilibrium. Naturally, the same effect works on solubility equilibria. a) The Ksp for Ag2SO3 = 1.50 X 10-14. What is the molar solubility of Ag2SO3 in a 3.8 M solution of lithium sulfite?

Expert Solution

Li2SO3(aq) --------------> 2Li^+ (aq) + SO3^2- (aq)

3.8M 3.8M

Ag2So3(s) ----------------> 2Ag^+ (aq) + SO3^2- (aq)

2x x +3.8

Ksp = [Ag^+]^2[SO3^2-]

1.5*10^-14 = (2x)^2(x+3.8) [ x+3.8 = 3.8 , x<<<<<<3.8]

1.5*10^-14 = (2x)^2(3.8)

x = 3.14*10^-8

The molar solubility of Ag2So3 = 3.14*10^-8 M

queen_honey_blossom answered 3 years ago

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