A packed bed reactor with present of catalyst: A(g) + 0.5 B(g) --> C(g) . ....

A packed bed reactor with present of catalyst: A_(g₎ + 0.5 B_(g) --> C(g) . . -r_A’ = k C_A^0.33C_B^0.66 . A student is tasked with designing the reactor and predicting the output. The student forgets to take into account the effects of pressure drop on the design. For a packed bed reactor with 100 g of catalyst, the exiting concentration of C that the student determines is likely to be equal/ greater than the exiting concentration that is predicted to exist if pressure drop is taken into account. Explain? (Less than is wrong)

Expert Solution

The one word answer for this question is concentration that the student determines is likely to be equal to the existing concentration for the given kinetics but the proof is quite big, please cope with it.

Amanda K answered 6 months ago

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