Question

A 215 g block of copper at 505.0°C is plunged into 1.000 kg of water (T = 23.4 °C) in an insulated container. What will be the final equilibrium T in °C of the water and the Cu? (sCu = 0.385 J g-1 °C-1)

Answer 1

Sol :-

The values provided in the question are as follows :-

Mass of block of copper = 215g=0.125kg

Mass of water = 1kg

Initial temperature of copper = 505 °C

Initial temperature of water = 23.4 °C

Specific heat of copper = 0.385 J g-1 °C-1 = 385 J kg-1 °C-1

Specific heat of water = 4200 J kg-1 °C-1

We have to find Final equlibrium temperature T in °C of water and copper as follws :-

Hence, the final equilibrium temperature in °C of the water and Cu is found to be = T = 28.62°C