Question

Hydrazine, N2H4, may react with oxygen to form nitrogen gas and water. N2H4(aq) + O2(g) -> N2(g) + 2H2O(l) If 3.65 g of N2H4 reacts and produces 0.950 L of N2, at 295 K and 1.00 atm, what is the percent yield of the reaction?

Answer 1

N2H4(aq) + O2(g) -------------------> N2(g) + 2H2O(l)

32.0g                                                   28 g

3.65 g                                                   ?

mass of N2 = 28 x 3.65 / 32

                  = 3.19 g

moles of N2 = 3.19 / 28 = 0.114

moles of actual N2 = P V / RT

                              = 1.00 x 0.950 / 0.0821 x 295

                               = 0.0392

percent yield of reaction = actual x 100 / theoretical

                                        = 0.0392 x 100 / 0.114

                                       = 34.4 %