Question

Write the correct ground state electronic configurations for the following atoms. Use the noble gas shorthand notation. Put superscripts in parentheses.

N

Ti

As

Xe

Answer 1

1)

Number of electron in N = 7

Electronic configuration is 1s2 2s2 2p3

Noble gas having lesser electron than N and closest to it is Helium (He)

Number of electron in He = 2

electronic configuration of He is: 1s2

So, electronic configuration of N in noble gas form is: [He] 2s2 2p3

2)

Number of electron in Ti = 22

Electronic configuration is 1s2 2s2 2p6 3s2 3p6 3d2 4s2

Noble gas having lesser electron than Ti and closest to it is Argon (Ar)

Number of electron in Ar = 18

electronic configuration of Ar is: 1s2 2s2 2p6 3s2 3p6

So, electronic configuration of Ti in noble gas form is: [Ar] 3d2 4s2

3)

Number of electron in As = 33

Electronic configuration is 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p3

Noble gas having lesser electron than As and closest to it is Argon (Ar)

Number of electron in Ar = 18

electronic configuration of Ar is: 1s2 2s2 2p6 3s2 3p6

So, electronic configuration of As in noble gas form is: [Ar] 3d10 4s2 4p3

4)

Number of electron in Xe = 54

Electronic configuration is 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p6

Noble gas having lesser electron than Xe and closest to it is Krypton (Kr)

Number of electron in Kr = 36

electronic configuration of Kr is: 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6

So, electronic configuration of Xe in noble gas form is: [Kr] 4d10 5s2 5p6