Question

6) Write the electron configurations for the following using noble gas core notation: a) Na b) S c) I

7)Given: N2 (g) + 3H2(g) ⇒ 2NH3 (g) ΔH = -92 kJ 92 kJ is the quantity of heat which is: a. gained from the surroundings when 1 mol of ammonia is formed. b. gained from the surroundings when 2 mol of ammonia are formed. c. lost to the surroundings when 1 mol of ammonia is formed. d. lost to the surroundings when 2 mol of ammonia are formed. e. none of the above. (also, is the reaction exothermic or endothermic?)

8)What are line spectra? Where do they come from?

Answer 1

6)

a)

Number of electron in Na = 11

Electronic configuration is 1s2 2s2 2p6 3s1

Noble gas having lesser electron than Na and closest to it is Neon (Ne)

Number of electron in Ne = 10

electronic configuration of Ne is: 1s2 2s2 2p6

So, electronic configuration of Na in noble gas form is: [Ne] 3s1

[Ne] 3s1

b)

Number of electron in S = 16

Electronic configuration is 1s2 2s2 2p6 3s2 3p4

Noble gas having lesser electron than S and closest to it is Neon (Ne)

Number of electron in Ne = 10

electronic configuration of Ne is: 1s2 2s2 2p6

So, electronic configuration of S in noble gas form is: [Ne] 3s2 3p4

[Ne] 3s2 3p4

c)

Number of electron in I = 53

Electronic configuration is 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p5

Noble gas having lesser electron than I and closest to it is Krypton (Kr)

Number of electron in Kr = 36

electronic configuration of Kr is: 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6

So, electronic configuration of I in noble gas form is: [Kr] 4d10 5s2 5p5

[Kr] 4d10 5s2 5p5

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