Question

In: Physics

Find the heat capacity of a block of unknown material. You will immerse the block, with...

Find the heat capacity of a block of unknown material. You will immerse the block, with its temperature known, into a known quantity of water, which is at a very different temperature than the block. After they reach equilibrium, they will be at the same final temperature. From the change of temperature of both, calculate the block's heat capacity.

NOTE: You can heat up or cool the block using hot water or ice water

HOW WILL I DO THIS ? ?? ? ? explain please physics wizards of chegg

Solutions

Expert Solution

Yes, this method is pretty common to find the specific heat of unknown material

the concept used here is that the metal will give up some heat when immersed in water and water will gain that heat. This means temperature of metal will decrease and temperature of water will increase. This increase / decrease will continue till a final equilibrium temperature is achieved

Let T be that equilibrium temperature

Let c be the specific heat of unknown metal

Let T' be the initial temperature of material and T'' be the initial temperature of water.

then

heat lost = heat gained

m material * c * Tmaterial = mwater * cwater * Twater

m material * c * ( T' - T) = mwater * cwater * ( T'' - T)

c = mwater * cwater * ( T'' - T) / m material * ( T' - T)

This way you can find the specific heat of any unknown material

--------------

cwater is known as 4186 J/ kg oC


Related Solutions

The specific heat capacity of an unknown metal was determined following Part A of the Experimental...
The specific heat capacity of an unknown metal was determined following Part A of the Experimental Procedure in this experiment. The following table is for Trial 1. Mass of unknown metal (g) 15.45 Temperature of unknown metal (oC) 95.4 Mass of water(g) 100.0 The specific heat of water (J/g.oC) 4.184 Temperature of water (oC) 23.0 Maximum temperature of water (oC) 25.8 Calculate the specific heat capacity of unknown metal (J/g.oC) _____
In a calorimetry experiment to determine the specific heat capacity of a metal block, the following...
In a calorimetry experiment to determine the specific heat capacity of a metal block, the following data was recorded: Quantity Mass of the metal block 0.50 kg Mass of empty calorimeter + Stirrer 0.06 kg Mass of calorimeter + stirrer + water 0.20 kg Mass of water 0.14 kg Initial Temperature of metal block 55.5 ⁰C Initial Temperature of water and calorimeter 22 ⁰C Final Temperature of block- water system 27.4 ⁰C Take the specific heat capacity of water to...
Part A) You have 67 grams of a unknown material, and you would like to find...
Part A) You have 67 grams of a unknown material, and you would like to find out its specific heat. You decide to heat it up to 100 C and put it in a 66 g aluminum cup (specific heat = 0.22 cal/(g C) that 200 grams of water (specific heat = 1 cal/(g C)). Usually this aluminum cup is in another cup so that the system is insulated. If both the cup and the aluminum cup are initially at...
You have 67 grams of a unknown material, and you would like to find out its...
You have 67 grams of a unknown material, and you would like to find out its specific heat. You decide to heat it up to 100 C and put it in a 66 g aluminum cup (specific heat = 0.22 cal/(g C) that 200 grams of water (specific heat = 1 cal/(g C)). Usually this aluminum cup is in another cup so that the system is insulated. If both the cup and the aluminum cup are initially at 20 C,...
A flask of water rests on a scale that reads100 . Then, a small block of unknown material is held completely submerged...
A flask of water rests on a scale that reads100 . Then, a small block of unknown material is held completely submerged in the water. The block does not touch any part of the flask, and the person holding the block will not tell you whether the block is being pulled up (keeping it from falling further) or pushed down (keeping it from bobbing back up).The experiment is repeated with the six different blocks listed below. In each case, the...
Heat Capacity Learning Goal: To understand the concepts of heat capacity, specific heat, and molar heat...
Heat Capacity Learning Goal: To understand the concepts of heat capacity, specific heat, and molar heat capacity. Heat capacity, C, is the amount of energy required to raise the temperature of a substance by exactly 1 degree Celsius. The energy needed to warm an object increases as the mass of that object increases. We see this in our everyday life. For example, we know that it takes much more energy to heat a large tank of water than a small...
Entropy & heat capacity: The definitions for the entropy and heat capacity are pretty similar. So,...
Entropy & heat capacity: The definitions for the entropy and heat capacity are pretty similar. So, what is actually the difference between dS=dq/T and cp = dq/dT? Apply a simple and plausible example to illustrate the different nature of S and cp.
A flask of water rests on a scale that reads 100 N. Then, a small block of unknown material is held completely submerged in the water.
A flask of water rests on a scale that reads 100 N. Then, a small block of unknown material is held completely submerged in the water. The block does not touch any part of the flask, and the person holding the block will not tell you whether the block is being pulled up (keeping it from falling further) or pushed down (keeping it from bobbing back up). The experiment is repeated with the six different blocks listed below. In each...
Take the heat capacity of ice as 2.108 J/(g*C) and the heat capacity of water as...
Take the heat capacity of ice as 2.108 J/(g*C) and the heat capacity of water as 4.184 J/(g*C) for this problem. For water, DHfus = 6.001 kJ/mol at 0 C. a. A 10.0 gram ice cube at -10.0 C is placed into 45.0 mL of water at 40 C. Determine the final physical state and temperature of the result. Calculate DS for the ice cube and the surrounding water, and Use the value DStot to explain why this process is...
The heat capacity, C, of an object is defined as the amount of heat...
  (II) The heat capacity, \(C\), of an object is defined as the amount of heat needed to raise its temperature by \(1 \mathrm{C}^{\circ}\). Thus, to raise the temperature by \(\Delta \mathrm{T}\) requires heat \(Q\) given by $$ \mathrm{Q}=\mathrm{C} \Delta \mathrm{T} $$ (a) Write the heat capacity \(C\) in terms of the specific heat, \(c\), of the material. (b) What is the heat capacity of \(1.0 \mathrm{~kg}\) of water? (c) Of \(45 \mathrm{~kg}\) of water?
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT