Question

You have 67 grams of a unknown material, and you would like to find out its specific heat. You decide to heat it up to 100 C and put it in a 66 g aluminum cup (specific heat = 0.22 cal/(g C) that 200 grams of water (specific heat = 1 cal/(g C)). Usually this aluminum cup is in another cup so that the system is insulated. If both the cup and the aluminum cup are initially at 20 C, and the equilibrium temperature of the system ends up being 22.5 degrees some time later. What is the specific heat of the material?

Answer 1

The concept used in this question is of heat balance which is equal to amount of energy lost by hot body is equal to the heat gained by the cold body , here in this question hot body is the unknown material and the cold body is the aluminium cup and water and after applying this concept i deduced the specific value of the material .

Note:- heat lost by the system is zero becasue the system is insulated .

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