The angular momentum of a flywheel having a rotational inertia of 0.407 kg·m2 about its central...

The angular momentum of a flywheel having a rotational inertia of 0.407 kg·m² about its central axis decreases from 5.40 to 0.970 kg·m²/s in 4.60 s. (a) What is the magnitude of the average torque acting on the flywheel about its central axis during this period? (b) Assuming a constant angular acceleration, through what angle does the flywheel turn? (c) How much work is done on the wheel? (d) What is the magnitude of the average power done on the flywheel?

Solutions

Expert Solution

Torque is required to rotate the flywheel in order to do so work , which is directly proportional to the Inertia of the flywheel , If the flywheel has more inertia then more amount of torque is required to rotate the flywheel because of more resistive force created by inertia of flywheel and then the corresponding work done on the flywheel is also more in that case , Angular displacement is the same as the distance in the linear motion , both linear and rotational motion are same , only the difference is of notation or the symbol , while the meanings are completely same , so if we want to solve rotational problem then firstly we have to imagine it as linear dimension problem concept then it can be easily solved.

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genius_generous answered 1 month ago

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