In: Economics
). Use incremental analysis to compare the two project options shown below. The number of periods is 10 and the MARR is 7%
Option A |
Option B |
∆A-B |
|
Initial Cost |
$275,000 |
$195,000 |
|
Annual Benefit |
$35,000 |
$25,000 |
|
Salvage Value |
$60,000 |
$50,000 |
Determine which option should be selected, based on the incremental analysis. State why (
Option B has a lower initial cost therefore consider it as the defender and option A has a higher initial cost therefore it will be considered as the Challenger to the the option B. In order to calculate incremental cash flow we are required to to subtract the cast of option B from option A.
A | B | ∆(A -B) | |
Initial cost | - $ 275,000 | - $ 195,000 | - $ 80,000 |
Annual benefit | $ 35,000 | $ 25,000 | $ 10,000 |
Salvage Value | $ 60,000 | $ 50,000 | $ 10,000 |
ii. The incremental cash flows Net Present worth can be expressed as
iii. Now, we are required to determine the incremental IRR using the trial and error method. Assume rate = 7% (=MARR)
At an interest rate of 7% the net present worth is negative therefore the required interest rate must be less than 7%. Now, assume rate equal to 5%
At an interest rate of 5% the NPW = $ 3,356.48 thus the required rate is greater than 5% and less than 7%.
The ∆IRR is in the range
Now we can determine the ∆IRR using the linear interpolation techniques as follows
The incremental IRR is less than the MARR thus the option A must be rejected and option B must be selected.
Select Option B. (Since, ∆IRR is less than MARR).
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