In: Physics
A rock is suspended by a light string. When the rock is in air, the tension in the string is 52.9 N . When the rock is totally immersed in water, the tension is 32.6 N . When the rock is totally immersed in an unknown liquid, the tension is 14.4 N .
What is the density of the unknown liquid?
Gravitational acceleration = g = 9.81 m/s2
Density of water = 1 = 1000 kg/m3
Density of the unknown liquid = 2
Weight of the rock = Tension in the string when the rock is air = W = 52.9 N
Volume of the rock = V
Buoyant force on the rock when immersed in water = F1 = 1Vg
Tension in the string when the rock is immersed in water = T1 = 32.6 N
When the rock is immersed in water the tension in the string and the buoyant force on it supports the weight of the rock.
W = F1 + T1
W = 1Vg + T1
52.9 = (1000)(9.81)V + 32.6
V = 2.0693 x 10-3 m3
Buoyant force on the rock when it is immersed in the unknown liquid = F2 = 2Vg
Tension in the string when the rock is immersed in unknown liquid = T2 = 14.4 N
When the rock is immersed in the unknown liquid the tension in the string and the buoyant force on it supports the weight of the rock.
W = F2 + T2
W = 2Vg + T2
52.9 = 2(2.0693x10-3)(9.81) + 14.4
2 = 1896.56 kg/m3
Density of the unknown liquid = 1896.56 kg/m3