Question

In: Economics

An airline is considering two types of engine systems for use in its planes. Each has...

An airline is considering two types of engine systems for use in its planes. Each has the same life and the same maintenance and repair record. System A costs ​$90,000 and uses 40,000 gallons per​ 1,000 hours of operation at the average load encountered in passenger service. System B costs ​$220,000 and uses 25,000 gallons per​ 1,000 hours of operation at the same level. Both engine systems have​ three-year lives before any major overhaul is required. On the basis of the initial​ investment, the systems have 10​% salvage values. If jet fuel costs ​$2.24 a gallon​ (year 1) and fuel consumption is expected to increase at the rate of 5​% per year because of degrading engine​ efficiency, which engine system should the firm​ install? Assume 5,000 hours of operation per year and a MARR of 9​%. Use the AE criterion. What is the equivalent operating cost per hour for each​ engine? Assume an​ end-of-year convention for the fuel cost.

The equivalent annual costs for system A are:

The equivalent annual costs for system B are:

Solutions

Expert Solution

Given

Slno

System A

Amount ($)

System B

Amount ($)

1

Initial cost

90000

220000

2

Estimated life

3 years

Estimated life

3 years

3

Salvage value

9000

Salvage value

22000

4

Fuel cost Year 01 (40000*5*2.24)

448000

Fuel cost Year 01 (25000*5*2.24)

280000

5

Fuel cost Year 02

(42000*5*2.24)

470400

Fuel cost Year 02

(26250*5*2.24)

294000

6

Fuel cost Year 02

(44000*5*2.24)

492800

Fuel cost Year 02

(27500*5*2.24)

308000

Solution

System A

Annual worth = 90000(A/P,9,3) - 9000(A/F,9,3) + 448000(P/F,9,1) (A/P,9,3) + 470400(P/F,9,2) (A/P,9,3) +492800(P/F,9,3) (A/P,9,3)

Using DCIF Tables

Annual worth = 90000(0.3951) - 9000(0.3051) + 448000(0.9174) (0.3951) + 470400(0.8417) (0.3951) +492800(0.7722) (0.3951)

The equivalent annual worth for system A are = $501982.9

System B

Annual worth = 220000(A/P,9,3) - 22000(A/F,9,3) + 280000(P/F,9,1) (A/P,9,3) + 294000(P/F,9,2) (A/P,9,3) +308000(P/F,9,3) (A/P,9,3)

Using DCIF Tables

Annual worth = 220000(0.3951) - 22000(0.3051) + 280000(0.9174) (0.3951) + 294000(0.8417) (0.3951) +308000(0.7722) (0.3951)

The equivalent annual worth for system B are = $373440.9


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