In: Statistics and Probability
In this assignment. you will determine the probability of several different z-scores.
Requirements:
We use the standard normal distribution table shown below.
(a) P(x<2.78) = 0.9973 (look for 2.7 row and 0.08 column)
(b) P(1.87<x<2.78) = P(x<2.78)-P(x<1.87) = 0.9973 - 0.9693 = 0.028
(c) P(-2.68<x<0.00) = P(x<0) - P(x<-2.68) = P(x<0) - [ 1 - P(x<2.68)] = 0.5 - [1 - 0.9963] = 0.5 - 0.0037 = 0.4963
(d) P(0.15<x<1.15) = P(x<1.15) - P(x<0.15) = 0.8749 - 0.5596 = 0.3153.
We solve only 4 parts per question in one post. Please post again for other solutions.