In: Statistics and Probability
Predict what the temperature anomaly would be at a CO2 level of 450 ppm
| CO2 (ppm) | Temp Anomaly (deg. C) |
| 335.40 | 0.2 |
| 336.84 | 0.34 |
| 338.75 | 0.43 |
| 340.11 | 0.14 |
| 341.45 | 0.39 |
| 343.05 | 0.21 |
| 344.65 | 0.2 |
| 346.12 | 0.25 |
| 347.42 | 0.41 |
| 349.19 | 0.52 |
| 351.57 | 0.38 |
| 353.12 | 0.53 |
| 354.39 | 0.53 |
| 355.61 | 0.24 |
| 356.45 | 0.28 |
| 357.10 | 0.39 |
| 358.83 | 0.57 |
| 360.82 | 0.49 |
| 362.61 | 0.55 |
| 363.73 | 0.85 |
| 366.70 | 0.6 |
| 368.38 | 0.58 |
| 369.55 | 0.68 |
| 371.14 | 0.8 |
| 373.28 | 0.78 |
| 375.80 | 0.69 |
| 377.52 | 0.88 |
| 379.80 | 0.78 |
| 381.90 | 0.86 |
| 383.79 | 0.65 |
| 385.60 | 0.79 |
| 387.43 | 0.92 |
| 389.90 | 0.79 |
| 391.65 | 0.77 |
| 393.85 | 0.81 |
| 396.52 | 0.88 |
| 398.65 | 0.96 |
| 400.83 | 1.23 |
Using excel to run the regression analysis:

Input the values as shown below:

The output is

The regression line is:
Y = -3.80890230414214 + 0.0120298273917277 * X
When X = 450
Y = 1.60452002213531
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