A −2.60%−2.60% grade meets a +1.60%+1.60% grade at station 44+25 and elevation 3386.96 ftft, 305-ftft curve,...

A −2.60%−2.60% grade meets a +1.60%+1.60% grade at station 44+25 and elevation 3386.96 ftft, 305-ftft curve, stakeout at half stations.answer should be 10 elevations

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Ally Wells answered 9 months ago

A −2.60% grade meets a +1.70% grade at station 44+25 and elevation 3386.96 ftft, 305-ftft curve,...

A −2.60% grade meets a +1.70% grade at station 44+25 and elevation 3386.96 ftft, 305-ftft curve, stakeout at half stations. Tabulate station elevations for an equal-tangent parabolic curve for the data given above. Express your answers, separated by commas, to six significant figures from lowest to highest elevation.

A −2.60% grade meets a +1.95% grade at station 44+25 and elevation 3386.96 ft, 315-ft curve,...

A −2.60% grade meets a +1.95% grade at station 44+25 and elevation 3386.96 ft, 315-ft curve, stakeout at half stations. Part A Tabulate station elevations for an equal-tangent parabolic curve for the data given above. Express your answers, separated by commas, to six significant figures from lowest to highest elevation. ftft, ftft, ftft, ftft, ftft, ftft, ftft, ftft, ftft, ftft SubmitRequest Answer Provide Feedback

Curve 2: A +7.00% grade meets a -6.00% grade at station 4+80 and elevation 705.70 ft,...

Curve 2: A +7.00% grade meets a -6.00% grade at station 4+80 and elevation 705.70 ft, 80-ft curve, staked 10ft apart. Get a rough estimate in cubic yards of how much soil that must be brought in (fill) and/or removed (cut) to create a 14-foot wide roadway that starts at your PVC/BVC, ends at your PVT/EVC, and follows your curve elevations. Make sure to state which curve your group was assigned in the calculations. Trapezoidal Area Estimation is key. ground...

A 0% grade meets a 3% grade at station 24+00.00 and an elevation of 372.15 ft....

A 0% grade meets a 3% grade at station 24+00.00 and an elevation of 372.15 ft. For a passing sight distance of 2,000 ft, find the following: a. Minimum length of the vertical curve that allows for passing using the minimum curve length equations. b. Calculate the elevation of the middle point of the curve. c. Calculate the elevation of the road at station 23+00.00.

A 3.0% grade passing at station 19+85.00 at an elevation of 99.10 m meets a -2.0%...

A 3.0% grade passing at station 19+85.00 at an elevation of 99.10 m meets a -2.0% grade passing at station 20+35.00 at an elevation of 99.60 m. Please note that these two elevations and stations DO NOT correspond to BVC and EVC. Determine the station and elevation of the point of intersection of the two grades./ If the highest point on the curve must lie at station 20+40.00, find the elevation of this point and the length of the curve...

A vertical curve has its PVI at station 14+75.00 and elevation 76.29 ft. The grade of...

A vertical curve has its PVI at station 14+75.00 and elevation 76.29 ft. The grade of the back tangent is 3.4%, the grade of the forward tangent is -4.8%, and the curve length is 450 ft. Determine the stations and elevations of the BVC and EVC. Determine the location and elevation of the high point of the curve. Determine the curve elevation at station 14+00 and station 16+00.

A negative 5% grade meets a positive 3% grade at vertex elevation 146.24m directly under an...

A negative 5% grade meets a positive 3% grade at vertex elevation 146.24m directly under an overpass bridge whose underside is at elevation 152.74 and carries another road across the grades at right angles.What is the longest parabolic curve that can be used to connect the two grades and at the same time provide at least 5 meter clearance under the bridge at its center line? If the underside of the bridge is level and is 12 meter wide, Find...

A grade g1=+2.00% intersects grade g2=−1.40% at a vertex whose station and elevation are 78+60 and...

A grade g1=+2.00% intersects grade g2=−1.40% at a vertex whose station and elevation are 78+60 and 7855.35 ft, respectively. An equal-tangent parabolic curve 505 ft long has been selected to join the two tangents. Compute station elevations for the curve, for stakeout at full stations.

A tangent section of highway has a -1.0% grade and ends at station 0+145 and elevation...

A tangent section of highway has a -1.0% grade and ends at station 0+145 and elevation 26 m. It must be connected to another section of highway that has a -1.0% grade and that begins at station 1 + 350 and elevation 40 m. The connecting alignment should consist of a sag curve, constant grade section, and crest curve, and be designed for a speed of 80 km/h. What is the lowest grade possible for the constant grade section that...

The following information is given about a vertical curve: Station of VPI = 150+00.00 feet Elevation...

The following information is given about a vertical curve: Station of VPI = 150+00.00 feet Elevation of VPI = 2500.00 feet L = 1000.00 feet g1 = -3.0% g2 = 1.0% (a) Find the stations and elevations of the BVC and EVC. (b) Also, what is the station and elevation of the lowest point of the curve? (c) Calculate the first and second differences on the curve elevations of the full stations

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