Question

In: Civil Engineering

A tangent section of highway has a -1.0% grade and ends at station 0+145 and elevation...

A tangent section of highway has a -1.0% grade and ends at station 0+145 and
elevation 26 m. It must be connected to another section of highway that has a -1.0% grade and that
begins at station 1 + 350 and elevation 40 m. The connecting alignment should consist of a sag
curve, constant grade section, and crest curve, and be designed for a speed of 80 km/h. What is the
lowest grade possible for the constant grade section that will complete the alignment?

Expert Solution

Answer:

Givin that:

A tangent section of highway has a -10% grade and ends at station 0+145 and elevation 26m.It must be connected to another section of highway that has 1 -10% grade and that begins at station 1 + 350 and elevation 40m.

L = Station of PVT - station of PVC

= (1 + 350) - (0 +145)

= 1 + 205

= 1205 m

= 40 -26 = 14m

For spad = 80 km / hr, from table

,

WKT,

Let

=

On solving

x = 1.18

%

Ally Wells answered 10 months ago

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