In: Statistics and Probability
The starting salaries of individuals with an MBA degree are normally distributed with a mean of $90,000 and a standard deviation of $20,000. Suppose we randomly select 16 of these individuals with an MBA degree. What is the standard deviation of the average starting salary for these individuals?
| a. | 
 $4,000  | 
|
| b. | 
 $5,000  | 
|
| c. | 
 $20,000  | 
|
| d. | 
 $1,666.67  | 
standard deviation of average starting salary = population standard deviation / sqrt(n) = 20000 / sqrt(16) = 5000
Option-B) $5000