In: Statistics and Probability
The starting salaries of individuals with an MBA degree are normally distributed with a mean of $90,000 and a standard deviation of $20,000. Suppose we randomly select 16 of these individuals with an MBA degree. What is the standard deviation of the average starting salary for these individuals?
a. |
$4,000 |
|
b. |
$5,000 |
|
c. |
$20,000 |
|
d. |
$1,666.67 |
standard deviation of average starting salary = population standard deviation / sqrt(n) = 20000 / sqrt(16) = 5000
Option-B) $5000