In: Statistics and Probability
Salaries for teachers in a particular elementary school district are normally distributed with a mean of $44,000 and a standard deviation of $6,500. We randomly survey ten teachers from that district. Find the 85th percentile for the sum of the sampled teacher's salaries to 2 decimal places.
Given that, mean (μ) = $44000 and
standard deviation = $6500
X ~ N(44000, 6500)
We want to find, the value of x such that, P(X ≤ x) = 0.85
Therefore, the 85th percentile for the sum of the sampled teacher's salaries is $50736.80
Note : Using Excel we get, Z0.85 = 1.03643
Excel Command : =NORMSINV (0.85) = 1.03643