Given the following vertical curve data: PVI at 19+ 00,L= 500 ft,g1= +2.5%,g2= -1%, and elevation...

Given the following vertical curve data: PVI at 19+ 00,L= 500 ft,g1= +2.5%,g2= -1%, and elevation of PVI = 723.86 ft.Compute the elevationsof the curve summit (i.e. high point)andfullstations.Assume that all symbols have their usual meaning.

Expert Solution

Ally Wells answered 11 months ago

Vertical Curves: Given g1 = -3%, g2 = 2%, L = 500', VPI Station of 100+00...

Vertical Curves: Given g1 = -3%, g2 = 2%, L = 500', VPI Station of 100+00 Calculate the PT Stationing.

A vertical curve has its PVI at station 14+75.00 and elevation 76.29 ft. The grade of...

A vertical curve has its PVI at station 14+75.00 and elevation 76.29 ft. The grade of the back tangent is 3.4%, the grade of the forward tangent is -4.8%, and the curve length is 450 ft. Determine the stations and elevations of the BVC and EVC. Determine the location and elevation of the high point of the curve. Determine the curve elevation at station 14+00 and station 16+00.

A sag vertical curve is to join a grade of g1=−3.50% to a grade of g2=−1.25%....

A sag vertical curve is to join a grade of g1=−3.50% to a grade of g2=−1.25%. What is the minimum length of the curve for acceptable passing sight distance at night, with headlight illumination? Express your answer in feet to five significant figures. there is no more info. this is all that was given to us.

The following information is given about a vertical curve: Station of VPI = 150+00.00 feet Elevation...

The following information is given about a vertical curve: Station of VPI = 150+00.00 feet Elevation of VPI = 2500.00 feet L = 1000.00 feet g1 = -3.0% g2 = 1.0% (a) Find the stations and elevations of the BVC and EVC. (b) Also, what is the station and elevation of the lowest point of the curve? (c) Calculate the first and second differences on the curve elevations of the full stations

A 1000-ft vertical curve connects a -1% grade to a -3.5% grade. If the vertical tangents...

A 1000-ft vertical curve connects a -1% grade to a -3.5% grade. If the vertical tangents intersect at sta. 38+60.24 and elevation 1,400.13 ft, develop an Excel spreadsheet to calculate the elevations of the grade line at each station from sta. 31+00 to 45+00. Include the elevations of the PVC and PVT.

Use the following data to calculate the layout of an equal tangent vertical curve by offsets...

Use the following data to calculate the layout of an equal tangent vertical curve by offsets for every full station. g1 = -1.20% g2 = +3.50% X PVI = 49+70 Y PVI = 5,893.48’ L = 1500’ , find the station and elevation of the high (or low) point of the curve.

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Given the following temperature and elevation data, determine the atmospheric stability and explain what type of plume behavior you would expect. Show all work: Elevation (m) Temperature (oC) 16.0 8.24 184.0 17.03 Question 1: A coal-fired electricity generation facility burns coal at a rate of 1.433 lbs/sec. The coal has a sulfur content of 3.25% by mass. Assuming that all but 5.00% of the sulfur is oxidized according to the reaction S + O2 → SO2, find the emissions rate...

Tabulate station elevations (stakeout at full stations) for an equal-tangent vertical curve for the following data...

Tabulate station elevations (stakeout at full stations) for an equal-tangent vertical curve for the following data given. (20 pts) • 500-ft curve • g1 = -3.00% • g2 = -1.25% • VPI at station 38 + 00 and elevation 560.00 ft

Vertical Curves: Problem 1 Given an equal tangent parabolic curve, a +0.50% grade meets a -2.50%...

Vertical Curves: Problem 1 Given an equal tangent parabolic curve, a +0.50% grade meets a -2.50% grade at Station 12+35.00 with an elevation of 305.12’, with L = 6 sta. Calculate the high point station. Provide the elevations at the PVC, PVT, High point, and at all full stations.

l The following data set is given. Determine whether it is reasonable to treat the following...

l The following data set is given. Determine whether it is reasonable to treat the following sample as though it comes from an approximately normal population. Include any charts or graphs you make in Excel here and justify your answer. 8.8 11.2 11.6 6.3 9.3 10.5 14.6 8.5 7.3 7.5 5.2 9.0 4.3 9.9 7.8 13.1 12.3 10.1

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