Question

In: Chemistry

V. Buffer Solution from Strong Base and Weak Acid Measure out 30.0 mL of 1.0 M...

V. Buffer Solution from Strong Base and Weak Acid Measure out 30.0 mL of 1.0 M CH3COOH and 5.0 mL of 1.0 M NaOH into a beaker.

1. Calculate the total volume. (include units) Vol _________

2. What is the concentration of acetic acid in this solution after mixing. (include units) [CH3COOH] _______

3. What is the concentration of sodium hydroxide in this solution after mixing. (include units) [NaOH] __________

4. Calculate the expected pH of this buffer solution. pH _________

_ 5. Measured pH of this buffer solution. pH ___3.77_______

6. What is the percent error between the calculated and measured value? What are some of the possible sources of this error? % error________

Solutions

Expert Solution

[CH3COOH] = 30 mL x 1 M = 30 mmol

[NaOH] = 5 mL x 1 M = 5 mmol

         CH3COOH   + NaOH       ------------------------> CH3COONa + H2O

Initial            30 mmol              5 mmol                                      0

----------------------------------------------------------------------------------------------------------------

after mixing        30-5                    0                                         5 mmol

                         = 25 mmol

Therefore, after mixing

[CH3COOH] = 25 mmol = 0.025 mol

[NaOH] = 0

[CH3COONa] = 5 mmol = 0.005 mol

We know that pKa of acetic acid CH3COOH = 4.75

From Hendeson-Hasselbalch equation,

pH = pKa + log [salt]/[acid]

     = 4.75 + log (0.005 mol/ 0.025 mol)

   = 4.05

pH = 4.05

Therefore,

1) Calculate the total volume. (include units) Vol = 30 ml + 5 ml = 35 ml = 0.035 L

2) What is the concentration of acetic acid in this solution after mixing. (include units) [CH3COOH] = 0.025 mol

   (or) 0.025 mol/ 0.035 L = 0.714 M

3) What is the concentration of sodium hydroxide in this solution after mixing. (include units) [NaOH] = 0

4) Calculate the expected pH of this buffer solution. pH = 4.05

6) What is the percent error between the calculated and measured value ?

                 = (4.05-3.77) / 3.77 x 100

                 = 7.4 %

    


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