Question

In: Chemistry

A 25.0 mL of a weak acid is titrated with a strong base (0.1 M). Calculate...

A 25.0 mL of a weak acid is titrated with a strong base (0.1 M). Calculate the pH of the solution during the titration if the weak acid concentration is 0.10 M and its Ka = 1.8 x 10-5 and 10.0 mL of base has been added. (Hint: use Henderson-Hasselbach equation).

a) pH = 4.56

b) pH= 5.28

c) pH= 4.74

Solutions

Expert Solution


Related Solutions

Weak acid with strong base: 25 mL of 0.1 M HCOOH with 0.1 M NaOH (pka...
Weak acid with strong base: 25 mL of 0.1 M HCOOH with 0.1 M NaOH (pka = 3.74) pH after adding following amounts of NaOH 18) 0 mL of NaOH 19) at half equivalence point 20) after adding 25 mL NaOH
Consider a weak base-strong acid titration in which 25 mL of 0.160 M ammonia is titrated...
Consider a weak base-strong acid titration in which 25 mL of 0.160 M ammonia is titrated with 0.160 M HCl. a) What is the pH of the ammonia solution before the addition of HCl? pKb of ammonia= 4.75 b) Calculate the pH after the addtion of 3 mL of HCl. c) Calculate the pH after the addition of 12.5mL of HCl. This is the half-neutralization point: the partial neutralization of ammonia converts some of the NH3 molecules to NH4+ ions...
25.0 mL of a 0.100 M NH3 is titrated with a strong acid. 0.100 M HCl....
25.0 mL of a 0.100 M NH3 is titrated with a strong acid. 0.100 M HCl. Calculate the pH of the NH3 solution at the following points during the titration: (Kb= 1.8 x 10^-5) A. Prior to the addition of any HCl. B: After the addition of 10.5 mL of a 0.100 M HCl. C: At the equivilance point. D: After the addition of 3 mL of 0.100 M HCl. Show your work.
A 25.0-mL sample of 0.20 M CH3NH2 (methanamine, a weak base) is titrated with 0.25 M...
A 25.0-mL sample of 0.20 M CH3NH2 (methanamine, a weak base) is titrated with 0.25 M HCl. What is the pH of the solution after 13.0 mL of HCl have been added to the base? The pKb of methanamine is 4.6 x 10-4 . What is the pH of the solution after 23.0 mL of HCl have been added to the base?
a 25.0 mL solution if 0.10 M acetic acid is titrated with 0.1 M NaOH solution....
a 25.0 mL solution if 0.10 M acetic acid is titrated with 0.1 M NaOH solution. the pH equivalence is
A weak acid is titrated with a strong base and the pH is measured at each...
A weak acid is titrated with a strong base and the pH is measured at each interval. It the equivalence point is reached when 30 mL of the base has been added, describe how the pKa of the acid can be determined.
50mL of 0.1M weak acid is titrated with 0.1 strong acid. Pka is 5.20 What is...
50mL of 0.1M weak acid is titrated with 0.1 strong acid. Pka is 5.20 What is the pH before the acid is added pH after adding 10mL of acid pH after 50 mL is added pH after 60mL is added Thank you for the help, I dont mind doing the amth, mainly need help with the equarions, thanks!
Consider a monoprotic weak acid (HA) that is titrated with a strong base. What is the...
Consider a monoprotic weak acid (HA) that is titrated with a strong base. What is the relationship between the strength of the weak acid and the pH of the solution at the equivalence point?  There is no relationship between the strength of the acid and the pH at the equivalence point. The pH at the equivalence point is always 7 in an acid base titration. The weaker the acid, the higher the pH at the equivalence point. The stronger the...
25.00 mL of 0.1 M acetic acid are titrated with 0.05 M NaOH. Calculate the pH...
25.00 mL of 0.1 M acetic acid are titrated with 0.05 M NaOH. Calculate the pH of the solution after addition of 50 mL of NaOH. Ka(CH3COOH) = 1.8 x 10-5.
classify each substance as a strong acid , weak acid , strong base or weak base...
classify each substance as a strong acid , weak acid , strong base or weak base KOH, Ca(OH)2, H 2SO4, HI, HCOOH, NaOH, HCN, C5H5N
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT