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In: Statistics and Probability

Three persons, A, B, and C, take turns in throwing a die. They throw in the...

Three persons, A, B, and C, take turns in throwing a die. They throw in the order A, B, C, A, B, C, A, B, etc., until someone wins. A wins by throwing a "one". B wins by throwing a "one" or a "two". C wins by throwing a "one", a "two", or a "three". Find the probability that each of the players is the winner.

Suppose to get 3/13, 5/13, 5/13

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Three persons, A, B, and C, take turns in throwing a die. They throw in the...
Three persons, A, B, and C, take turns in throwing a die. They throw in the order A, B, C, A, B, C, A, B, etc., until someone wins. A wins by throwing a "one". B wins by throwing a "one" or a "two". C wins by throwing a "one", a "two", or a "three". Find the probability that each of the players is the winner. The answers are 3/13, 5/13, 5/13 Please show your work
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