Question

In: Math

Five persons A, B, C, D, and E are seated at random in a row of...

Five persons A, B, C, D, and E are seated at random in a row of seats numbered 1, 2, 3, 4, and 5.

a) Find the probability that A is seated on seat 2.

b) FInd the probability that A and B are not seated with each other.

Solutions

Expert Solution

a) P(A is seated on seat 2) = 4!/5! = 0.2

b) P(A and B are not seated with each other) = 1 - P(A and B are seated with each other)

                                                                         = 1 - (4! * 2!)/5!

                                                                          = 1 - 0.4 = 0.6

milcah answered 1 year ago
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