In: Statistics and Probability
Data on corneal thickness in microns for 8 patients with glaucoma in one eye but not in the other is shown below. Patient 1 2 3 4 5 6 7 8 Normal 484 478 492 444 436 398 464 476 Galucoma 488 478 480 426 440 410 458 460 a) At alpha = 0.10, do the data suggest that mean corneal thickness is greater in normal eyes than in eyes with glaucoma? Assume that paired differences are normally distributed. (Use the critical value approach and the P-value approach). b) Find a 99% confidence interval for the difference between the mean corneal thickness of normal and glaucoma affected eyes. c) Use the Paired Wilcoxcon Signed-Rank Test at alpha = 0.10.
a)
Sample #1 | Sample #2 | difference , Di =sample1-sample2 |
484 | 488 | -4 |
478 | 478 | 0 |
492 | 480 | 12 |
444 | 426 | 18 |
436 | 440 | -4 |
398 | 410 | -12 |
464 | 458 | 6 |
476 | 460 | 16 |
sample 1 | sample 2 | Di | |
sum = | 3672 | 3640 | 32 |
mean= | 459 | 455 | 4 |
Ho : µd= 0
Ha : µd > 0
Level of Significance , α = 0.01
sample size , n = 8
mean of sample 1, x̅1= 459.0000
mean of sample 2, x̅2= 455.0000
mean of difference , D̅ = 4
std dev of difference , Sd =
10.743769
std error , SE = Sd / √n = 3.7985
t-statistic = (D̅ - µd)/SE = 1.0530
Degree of freedom, DF= n - 1 = 7
t-critical value , t* = 1.415
p-value = 0.16365
Conclusion: p-value>α =0.10, Do not reject
null hypothesis
so, there is no enough evidence to conclude that mean corneal thickness is greater in normal eyes than in eyes with glaucoma at α=0.10
b)
Degree of freedom, DF= n - 1 = 7
t-critical value = t α/2,df =
3.4995
std dev of difference , Sd =
10.7438
std error , SE = Sd / √n = 3.7985
margin of error, E = t*SE = 13.293
mean of difference , D̅ = 4.0000
confidence interval is
Interval Lower Limit= D̅ - E =
-9.2928
Interval Upper Limit= D̅ + E =
17.2928
c)
Paired Wilcoxcon Signed-Rank
Ho: mean corneal thickness is equal in normal eyes than in eyes with glaucoma
H1: mean corneal thickness is greater in normal eyes than in eyes with glaucoma
sample 1 | sample 2 | difference=sample1-sample 2 | absolue difference | rank | rank if positive | rank if negative |
484 | 488 | -4 | 4 | 1.5 | 1.5 | |
478 | 478 | 0 | ||||
492 | 480 | 12 | 12 | 4.5 | 4.5 | |
444 | 426 | 18 | 18 | 7 | 7 | |
436 | 440 | -4 | 4 | 1.5 | 1.5 | |
398 | 410 | -12 | 12 | 4.5 | 4.5 | |
464 | 458 | 6 | 6 | 3 | 3 | |
476 | 460 | 16 | 16 | 6 | 6 |
number of non zero difference , n = 7
sum of positive ranks, W+ = 20.5
sum of negative ranks , W- = 7.5
T = W+ = 20.5
mean ,µ = n(n+1)/4 = 14
std dev ,σ = √(n(n+1)(2n+1)/24) = 5.916
Z-stat = (T - µ)/σ = 1.099
Z*, Z critical value = 1.28
P-value = 0.13594
Conclusion: P-value>α=0.01 , Do not reject
null hypothesis
so, there is no enough evidenc eto conclude that mean corneal
thickness is greater in normal eyes than in eyes with glaucoma