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In: Statistics and Probability

Data on corneal thickness in microns for 8 patients with glaucoma in one eye but not...

Data on corneal thickness in microns for 8 patients with glaucoma in one eye but not in the other is shown below. Patient 1 2 3 4 5 6 7 8 Normal 484 478 492 444 436 398 464 476 Galucoma 488 478 480 426 440 410 458 460 a) At alpha = 0.10, do the data suggest that mean corneal thickness is greater in normal eyes than in eyes with glaucoma? Assume that paired differences are normally distributed. (Use the critical value approach and the P-value approach). b) Find a 99% confidence interval for the difference between the mean corneal thickness of normal and glaucoma affected eyes. c) Use the Paired Wilcoxcon Signed-Rank Test at alpha = 0.10.

Solutions

Expert Solution

a)

Sample #1 Sample #2 difference , Di =sample1-sample2
484 488 -4
478 478 0
492 480 12
444 426 18
436 440 -4
398 410 -12
464 458 6
476 460 16
sample 1 sample 2 Di
sum = 3672 3640 32
mean= 459 455 4

Ho :   µd=   0
Ha :   µd > 0
      
Level of Significance ,    α =    0.01
      
sample size ,    n =    8
      
mean of sample 1,    x̅1=   459.0000
      
mean of sample 2,    x̅2=   455.0000
      
mean of difference ,    D̅ =   4
      
std dev of difference , Sd =        10.743769


      
std error , SE =    Sd / √n =    3.7985
      
t-statistic =    (D̅ - µd)/SE =    1.0530


      
Degree of freedom, DF=   n - 1 =    7
t-critical value , t* = 1.415

      
p-value =        0.16365
Conclusion:     p-value>α =0.10, Do not reject null hypothesis  

so, there is no enough evidence to conclude that mean corneal thickness is greater in normal eyes than in eyes with glaucoma at α=0.10

b)

Degree of freedom, DF=   n - 1 =    7
t-critical value =    t α/2,df =    3.4995
      
std dev of difference , Sd =        10.7438
      
std error , SE =    Sd / √n =    3.7985
margin of error, E =    t*SE =    13.293
      
mean of difference ,    D̅ =   4.0000
confidence interval is       
Interval Lower Limit=   D̅ - E =   -9.2928
Interval Upper Limit=   D̅ + E =   17.2928

c)

Paired Wilcoxcon Signed-Rank

Ho: mean corneal thickness is equal in normal eyes than in eyes with glaucoma

H1: mean corneal thickness is greater in normal eyes than in eyes with glaucoma

sample 1 sample 2 difference=sample1-sample 2 absolue difference rank rank if positive rank if negative
484 488 -4 4 1.5 1.5
478 478 0
492 480 12 12 4.5 4.5
444 426 18 18 7 7
436 440 -4 4 1.5 1.5
398 410 -12 12 4.5 4.5
464 458 6 6 3 3
476 460 16 16 6 6

number of non zero difference , n =    7
  
sum of positive ranks, W+ =    20.5
sum of negative ranks , W- =   7.5
  
T = W+ = 20.5
  
mean ,µ = n(n+1)/4 =    14
  
std dev ,σ = √(n(n+1)(2n+1)/24) =   5.916

Z-stat = (T - µ)/σ =    1.099
  
Z*, Z critical value = 1.28
  
P-value =    0.13594
Conclusion:     P-value>α=0.01 , Do not reject null hypothesis
so, there is no enough evidenc eto conclude that mean corneal thickness is greater in normal eyes than in eyes with glaucoma


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