Question

In: Statistics and Probability

Glaucoma is a disease of the eye that is manifested by high intraocular pressure. The distribution...

Glaucoma is a disease of the eye that is manifested by high intraocular pressure. The distribution of intraocular pressure in the general population is approximately normal with mean 16 mm Hg and standard deviation 3 mm Hg. In a random sample of 35 people, find the probability that the average intraocular pressure is between 15.9 and 16.5. (answer to 4 decimals)

Expert Solution

Solution :

Given that ,

mean = = 16

standard deviation = =3

n = 35

= 16

= / $\sqrt$ n= 3 / $\sqrt$ 35=0.5071

P(15.9< < 16.5) = P[(15.9-16) /0.5071 < ( - ) / < (16.5-16) / 0.5071 )]

= P(-0.20 < Z < 0.99)

= P(Z < 0.99) - P(Z < -0.20)

Using z table

=0.8389-0.4207

=0.4182

probability= 0.4182

orchestra answered 2 years ago

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