In: Chemistry
Co(s) → Co2+(aq) + 2e
Fe2+(aq) + 2e-→ Fe(s)
b) Calculate the standard cell potential for this voltaic cell. c) Calculate the cell potential for this voltaic cell at 298 K if it is constructed using solutions of 0.14 M Co(NO3)2 and 0.27 M Fe(NO3)2. d) When looking at the magnitude of this potential, what can be concluded about the electrochemical cell?
anode : Co(s) → Co2+(aq) + 2e , Eo = -0.28 V
cathode : Fe2+(aq) + 2e-→ Fe(s) , Eo = -0.44 V
b) standard cell potential = Eo cathode - Eo anode
= -0.44 + 0.28
= - 0.16 V
c) Q = [Co2+ / Fe2+]
= (0.14 / 0.27)
= 0.5185
cell potential = Eocell - 0.05916 / n log Q
= -.016 - 0.05916/2 * log (0.5185)
= - 0.00756 V
d)
Ecell is negative . so the reaction is not spontaneous that means the cell doesnot work