Co(s) → Co2+(aq) + 2e Fe2+(aq) + 2e-→ Fe(s) b) Calculate the standard cell potential for...

Co(s) → Co2+(aq) + 2e

Fe2+(aq) + 2e-→ Fe(s)

b) Calculate the standard cell potential for this voltaic cell. c) Calculate the cell potential for this voltaic cell at 298 K if it is constructed using solutions of 0.14 M Co(NO3)2 and 0.27 M Fe(NO3)2. d) When looking at the magnitude of this potential, what can be concluded about the electrochemical cell?

Solutions

Expert Solution

anode : Co(s) → Co2+(aq) + 2e , Eo = -0.28 V

cathode : Fe2+(aq) + 2e-→ Fe(s) , Eo = -0.44 V

b) standard cell potential = Eo cathode - Eo anode

= -0.44 + 0.28

= - 0.16 V

c) Q = [Co2+ / Fe2+]

= (0.14 / 0.27)

= 0.5185

cell potential = Eocell - 0.05916 / n log Q

= -.016 - 0.05916/2 * log (0.5185)

= - 0.00756 V

Ecell is negative . so the reaction is not spontaneous that means the cell doesnot work

queen_honey_blossom answered 1 year ago

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