In: Chemistry
What is the pH at 25 ∘C of water saturated with CO2 at a partial pressure of 1.20 atm ? The Henry's law constant for CO2 at 25 ∘C is 3.1×10−2mol/L-atm. The CO2 is an acidic oxide, reacting with H2O to form H2CO3.
C = Kh/P as per Henry law where C = Molarity of CO2 dissolved , P = partial pressure = 1.2 atm ,
Kh is henry cosntant = 3.1 x 10^-2 mol/Latm
C = ( 3.1 x 10^-2 mol/Latm) / ( 1.2 atm)
= 0.0258 M
CO2 combines with H2O to form H2CO3 , hence H2CO3 Molarity = 0.0258 M
H2CO3 (aq) <----> H+ (aq) + HCO3- (aq)
Initial 0.0258 0 0
at equilibrium 0.0258-X X X
Ka = [H+] [HCO3-] /[H2CO3]
5 x 10^-7 = X^2 / ( 0.0258-X) here we approximate 0.0258-X as 0.0258 sicne X value is small as Ka is small
X = [H+] = 1.137 x 10^-4
pH = -log ( 1.137 x 10^-4) = 3.94