Question

In: Chemistry

Calculate the delta G'naught. Malate + pyruvate --> oxaloacetate + lactate Oxaloacetate + (2H+) + (2e-)...

Calculate the delta G'naught.

Malate + pyruvate --> oxaloacetate + lactate

Oxaloacetate + (2H+) + (2e-) --> malate E'naught= -0.166

Pyruvate + (2H+) + (2e-) --> lactate E'naught = -0.185

Not sure how to calculate the delta G'naught. Both are recieving electrons. But my guess is that the reduction of malate is more favorable becaue of a higher E'naught. Therefore the overall reaction, guessing, would tend toward the left.

Expert Solution

Oxaloacetate + (2H+) + (2e-) --> malate E⁰= -0.166V

Pyruvate + (2H+) + (2e-) --> lactate E⁰ = -0.185V

malate -------------------> Oxaloacetate + (2H+) + (2e-) E⁰ = 0.166v

Pyruvate + (2H+) + (2e-) -------> lactate E⁰ = -0.185V

-------------------------------------------------------------------------------------------'

Malate + pyruvate --> oxaloacetate + lactate E⁰ Cell = -0.019V

n= 2

G⁰ = -nE⁰cell*F

= -2*-0.019*96500

= 3667J = 3.667KJ

G⁰ > 0 it non spontaneous reaction.

The overall reaction to wards revers(left side)

queen_honey_blossom answered 2 years ago

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