Question

Calculate the delta G'naught.

Malate + pyruvate --> oxaloacetate + lactate

Oxaloacetate + (2H+) + (2e-) --> malate E'naught= -0.166

Pyruvate + (2H+) + (2e-) --> lactate E'naught = -0.185

Not sure how to calculate the delta G'naught. Both are recieving electrons. But my guess is that the reduction of malate is more favorable becaue of a higher E'naught. Therefore the overall reaction, guessing, would tend toward the left.

Answer 1

Oxaloacetate + (2H+) + (2e-) --> malate    E⁰= -0.166V

Pyruvate + (2H+) + (2e-) --> lactate      E⁰ = -0.185V

malate -------------------> Oxaloacetate + (2H+) + (2e-)       E⁰ = 0.166v

Pyruvate + (2H+) + (2e-) -------> lactate    E⁰ = -0.185V

-------------------------------------------------------------------------------------------'

Malate + pyruvate --> oxaloacetate + lactate                             E⁰ Cell = -0.019V

n= 2

G⁰   = -nE⁰cell*F

            = -2*-0.019*96500

            = 3667J    = 3.667KJ

G⁰ > 0 it non spontaneous reaction.

The overall reaction to wards revers(left side)