In: Statistics and Probability
Class |
Exam Score |
Class |
Exam Score |
Class |
Exam Score |
1 |
87 |
2 |
87 |
3 |
89 |
1 |
86 |
2 |
85 |
3 |
91 |
1 |
76 |
2 |
99 |
3 |
96 |
1 |
56 |
2 |
85 |
3 |
87 |
1 |
78 |
2 |
79 |
3 |
89 |
1 |
98 |
2 |
81 |
3 |
90 |
1 |
77 |
2 |
82 |
3 |
89 |
1 |
66 |
2 |
78 |
3 |
96 |
1 |
75 |
2 |
85 |
3 |
96 |
1 |
67 |
2 |
91 |
3 |
93 |
(I). Group |
(J) Group |
Mean Difference |
Significance |
Different? |
PowerP’s |
Black Markers |
-8.60 |
.071 |
|
PowerP’s |
Color Markers |
-15.00 |
.001 |
|
Black Markers |
Color Markers |
-6.4 |
.257 |
To test the null hypothesis
ie The three teaching methods yields the same score or there is no difference in the teaching methods
against the alternative that atleast one method differ from the others
An ANOVA test has been conducted to test the above hypothesis and the table is given below
F value is calculated using the formula =MS between/MS within=566.533/64.385=8.799
The pvalue tells us to reject the null hypothesis at 5% significance level . since p value <0.05
Also the F value > F critical value which again directs us to reject the null hypothesis
(I). Group |
(J) Group |
Mean Difference |
Significance |
|
|
PowerP’s |
Black Markers |
-8.60 |
.071 |
NOT Different | |
PowerP’s |
Color Markers |
-15.0 |
.001 |
Different | |
Black Markers |
Color Markers |
-6.4 |
.257 |
NOT Different |
power point and color markers are statistically significant at 5% significance level.