In: Physics
(a) A block of mass m = 3.90 kg is suspended as shown in the diagram below. Assume the pulley to be frictionless and the mass of the strings to be negligible. If the system is in equilibrium, what will be the reading of the spring scale in newtons? N
(b) Two blocks each of mass m = 3.90 kg are connected as shown in the diagram below. Assume the pulley to be frictionless and the mass of the strings to be negligible. If the system is in equilibrium, what will be the reading of the spring scale in newtons? N
(c) A block of mass m = 3.90 kg is in equilibrium on an incline plane of angle θ = 28.0° when connected as shown in the diagram below. Assume the mass of the strings to be negligible. If the system is in equilibrium, what will be the reading of the spring scale in newtons? N
(b) Two blocks each of mass m = 3.93 kg are connected as shown in the diagram below.
If the system is in equilibrium, then the reading of the spring scale which will be given as :
we know that, FN = m g
where, g = acceleration due to gravity = 9.8 m/s2
FN = 2 (3.9 kg) (9.8 m/s2)
FN = 76.4 N
(c) A block of mass m = 3.9 kg is in equilibrium on an incline plane of angle, = 280 when connected as shown in the diagram below.
If the system is in equilibrium, then the reading of the spring scale which will be given as :
using an equation, we have
FN = mg cos
where, m = mass of the block = 3.9 kg
= inclination angle = 28 degree
then, we have
FN = (3.9 kg) (9.8 m/s2) cos 280
FN = (38.2 N) (0.8829)
FN = 33.7 N