In: Statistics and Probability
In an article in
Marketing Science, Silk and Berndt investigate the output
of advertising agencies. They describe ad agency output by finding
the shares of dollar billing volume coming from various media
categories such as network television, spot television, newspapers,
radio, and so forth.
(a)
Suppose that a random sample of 405 U.S. advertising agencies gives
an average percentage share of billing volume from network
television equal to 7.42%, and assume that σ equals 1.44
percent. Calculate a 95% confidence interval for the mean
percentage share of billing volume from network television for the
population of all U.S. advertising agencies. (Round your
answers to 3 decimal places.)
The 95% confidence
interval is
[,
].
(b)
Suppose that a random sample of 405 U.S. advertising agencies gives
an average percentage share of billing volume from spot television
commercials equal to 12.40%, and assume that σ equals 1.56
percent. Calculate a 95% confidence interval for the mean
percentage share of billing volume from spot television commercials
for the population of all U.S. advertising agencies. (Round
your answers to 3 decimal places.)
The 95% confidence
interval is
[,
].
(c)
Compare the confidence intervals in parts a and
b. Does it appear that the mean percentage share of
billing volume from spot television commercials for U.S.
advertising agencies is greater than the mean percentage share of
billing volume from network television? Explain.
(Click to select)YesNo , confidence interval in (b) is totally (Click to select)belowabove the confidence interval in (a).
Formula for Confidence Interval for population Mean When Population Standard deviation is known
a. Given
Given | |
Sample average percentage share of billing volume from network television : Sample Mean : | 7.42 |
Population Standard Deviation : | 1.44 |
Number of U.S. advertising agencies in the sample Sample Size : n | 405 |
Confidence Level : | 95 |
: (100-95 )/100 | 0.05 |
/2 | 0.025 |
Z0.025 | 1.96 |
95% confidence interval for the mean percentage share of billing volume from network television for the population of all U.S. advertising agencies
95% confidence interval for the mean percentage share of billing volume from network television for the population of all U.S. advertising agencies : (7.2798,7.5602)
b.
Given | |
Sample average percentage share of billing volume from spot television commercials : Sample Mean : | 12.40 |
Population Standard Deviation : | 1.56 |
Number of U.S. advertising agencies in the sample Sample Size : n | 405 |
Confidence Level : | 95 |
: (100-95 )/100 | 0.05 |
/2 | 0.025 |
Z0.025 | 1.96 |
95% confidence interval for the mean percentage share of billing volume from spot television commercials for the population of all U.S. advertising agencies
95% confidence interval for the mean percentage share of billing volume from spot television commercials for the population of all U.S. advertising agencies : (12.2481,12.5519)
(c)
Does it appear that the mean percentage share of billing volume from spot television commercials for U.S. advertising agencies is greater than the mean percentage share of billing volume from network television
Ans : Yes;
As lower confidence limit of (b) : 12.2481 > Upper confidence limit of (a) : 7.5602
so , the confidence interval in (b) is (12.2481, 12.5519) is totally above the confidence interval in (a) (7.2798,7.5602)
confidence interval in (b) is totally above the confidence interval in (a)
Ans : Yes ; Above