In: Statistics and Probability
A baseball coach reviews the number of runs hit per game for the past several seasons. Since the team plays so many games, he selects a random sample of 10 games and records the number of runs scored in each game. The average number of runs scored is 8 with a standard deviation of 2.4 runs.
Compute the margin of error given a confidence level of 99%.
SOLUTION:
From given data,
A baseball coach reviews the number of runs hit per game for the past several seasons. Since the team plays so many games, he selects a random sample of 10 games and records the number of runs scored in each game. The average number of runs scored is 8 with a standard deviation of 2.4 runs.
Sample size = n = 10
= 8
Standard deviation = = 2.4
Compute the margin of error given a confidence level of 99%.
99% confidence level
Confidence level is 99%
99% = 99/100 = 0.99
= 1 - Confidence interval = 1-0.99 = 0.01
/2 = 0.01 / 2
= 0.005
Z/2 = Z0.005 = 2.576
Margin of error = E = Z/2 * (/sqrt(n))
E = 2.576 * (2.4/sqrt(10))
E = 2.576 * 0.7589466
E = 1.955046
E = 1.955 (Round your answer to three decimal places.)
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