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In: Statistics and Probability

A baseball coach reviews the number of runs hit per game for the past several seasons....

A baseball coach reviews the number of runs hit per game for the past several seasons. Since the team plays so many games, he selects a random sample of 10 games and records the number of runs scored in each game. The average number of runs scored is 8 with a standard deviation of 2.4 runs.

Compute the margin of error given a confidence level of 99%.

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SOLUTION:

From given data,

A baseball coach reviews the number of runs hit per game for the past several seasons. Since the team plays so many games, he selects a random sample of 10 games and records the number of runs scored in each game. The average number of runs scored is 8 with a standard deviation of 2.4 runs.

Sample size = n = 10

= 8

Standard deviation = = 2.4

Compute the margin of error given a confidence level of 99%.

99% confidence level

Confidence level is 99%

99% = 99/100 = 0.99

= 1 - Confidence interval = 1-0.99 = 0.01

/2 = 0.01 / 2

= 0.005

Z/2 = Z0.005  = 2.576

Margin of error = E = Z/2 * (/sqrt(n))

E = 2.576 * (2.4/sqrt(10))

E = 2.576 * 0.7589466

E = 1.955046

E = 1.955   (Round your answer to three decimal places.)

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