Question

A baseball coach reviews the number of runs hit per game for the past several seasons. Since the team plays so many games, he selects a random sample of 10 games and records the number of runs scored in each game. The average number of runs scored is 9 with a standard deviation of 3.6 runs. Compute the margin of error given a confidence level of 99%. (Use a table or technology. Round your answer to three decimal places.)

Answer 1

SOLUTION:

From given data,

A baseball coach reviews the number of runs hit per game for the past several seasons. Since the team plays so many games, he selects a random sample of 10 games and records the number of runs scored in each game. The average number of runs scored is 9 with a standard deviation of 3.6 runs.

Sample size = n = 10

= 9

Standard deviation = = 3.6

Compute the margin of error given a confidence level of 99%.

99% confidence level

Confidence level is 99%

99% = 99/100 = 0.99

= 1 - Confidence interval = 1-0.99 = 0.01

/2 = 0.01 / 2

= 0.005

Z_/2 = Z_0.005  = 2.576

Margin of error = E = Z_/2 * (/sqrt(n))

E = 2.576 * (3.6 /sqrt(10))

E = 2.576 * 1.138419957

E = 2.932569

E = 2.933   (Round your answer to three decimal places.)

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